(x+5)(x-5)=x^2-25

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Solution for (x+5)(x-5)=x^2-25 equation: 



(x+5)(x-5)=x^2-25

We move all terms to the left:

(x+5)(x-5)-(x^2-25)=0

We use the square of the difference formula

x^2-(x^2-25)-25=0

We get rid of parentheses

x^2-x^2+25-25=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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